20-5x+4x^2=0

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Solution for 20-5x+4x^2=0 equation: 



20-5x+4x^2=0

a = 4; b = -5; c = +20;
Δ = b2-4ac
Δ = -52-4·4·20
Δ = -295
Delta is less than zero, so there is no solution for the equation

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